VALID 1Z1-071 TEST BLUEPRINT - 1Z1-071 TEST PRICE

Valid 1z1-071 Test Blueprint - 1z1-071 Test Price

Valid 1z1-071 Test Blueprint - 1z1-071 Test Price

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Just register for the 1z1-071 examination and download 1z1-071 updated pdf dumps today. With these 1z1-071 real dumps you will not only boost your Oracle Database SQL test preparation but also get comprehensive knowledge about the Oracle Database SQL examination topics.

Oracle 1z1-071: Oracle Database SQL certification exam includes 73 questions that must be completed within a maximum of 100 minutes. The questions range from multiple-choice to hands-on, practical exams. It is essential for candidates to prepare well for the exam and obtain all the necessary training before taking the test. 1z1-071 Exam is administered by Pearson VUE, a leading provider of certification exams.

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Free PDF Oracle - 1z1-071 - Oracle Database SQL Unparalleled Valid Test Blueprint

For the Oracle Database SQL (1z1-071) web-based practice exam no special software installation is required. Because it is a browser-based Oracle Database SQL (1z1-071) practice test. The web-based Oracle Database SQL (1z1-071) practice exam works on all operating systems like Mac, Linux, iOS, Android, and Windows.

Oracle 1z1-071 exam is an important certification for individuals who work with Oracle Database. It covers a wide range of topics related to SQL and database management, and passing the exam demonstrates a strong foundation in these areas. Whether you are a developer, administrator, or analyst, passing 1z1-071 Exam can help advance your career in the field of database management.

Oracle Database SQL Sample Questions (Q131-Q136):

NEW QUESTION # 131
View the exhibit and examine the data in the PROJ_TASK_DETAILS table. (Choose the best answer.)

The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them.
The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result?

  • A. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p LEFT OUTER JOIN proj_task_details d
    ON (p.based_on = d.task_id);
  • B. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p FULL OUTER JOIN proj_task_details d
    ON (p.based_on = d.task_id);
  • C. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p JOIN proj_task_details d
    ON (p.task_id = d.task_id);
  • D. SELECT p.task_id, p.based_on, d.task_in_charge
    FROM proj_task_details p JOIN proj_task_details d
    ON (p.based_on = d.task_id);

Answer: A


NEW QUESTION # 132
View the Exhibit and examine the structure of the PRODUCT_INFORMATIONtable.

You want to see the product names and the date of expiration of warranty for all the products, if the product is purchased today. The products that have no warranty should be displayed at the top and the products with maximum warranty period should be displayed at the bottom.
Which SQL statement would you execute to fulfill this requirement?
SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"

  • A. FROM product_information
    ORDER BY SYSDATE
    SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"
  • B. FROM product_information
    WHERE warranty_period > SYSDATE
  • C. FROM product_information
    ORDER BY SYSDATE+warranty_period
    SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"
  • D. FROM product_information
    ORDER BY SYSDATE-warranty_period
    SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"

Answer: C


NEW QUESTION # 133
View the Exhibit and examine the structure of ORDER_ITEMS and ORDERS tables.

You need to remove from the ORDER_ITEMS table those rows that have an order status of 0 or 1 in the ORDERS table.
Which two DELETE statements are valid (Choose two.)

  • A. DELETE *FROM order_itemsWHERE order_id IN (SELECT order_id)FROM ordersWHERE order_status IN (0,1));
  • B. DELETE FROM order_items iWHERE order_id = (SELECT order_id FROM orders oWHERE i.order_id = o.order_id AND order_status IN (0,1));
  • C. DELETEFROM order_itemsWHERE order_id IN (SELECT order_idFROM ordersWHERE orders_status in (0,1));
  • D. DELETEFROM (SELECT * FROM order_items I,orders oWHERE i.order_id = o.order_id AND order_status IN (0,1));

Answer: C,D


NEW QUESTION # 134
View the Exhibit and examine the structure in the EMPLOYEES tables.

Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=10;
What would be the outcome of the above SQL statement?

  • A. The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.
  • B. The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.
  • C. The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.
  • D. The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.

Answer: A


NEW QUESTION # 135
The PRODUCT_INFORMATION table has a UNIT_PRICE column of data type NUMBER(8, 2).
Evaluate this SQL statement:
SELECT TO_CHAR(unit_price,'$9,999') FROM PRODUCT_INFORMATION;
Which two statements are true about the output?

  • A. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,023.
  • B. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,023.
  • C. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as #####
  • D. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,0236.
  • E. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,024.

Answer: B,C

Explanation:
The TO_CHAR function is used to convert a number to a string format in Oracle SQL. In this format mask '$9,999', the dollar sign is a literal, and the 9 placeholders represent a digit in the output. The comma is a digit group separator.
A . This statement is incorrect because the format model does not have enough digit placeholders to display the full number 1023.99; it would round it to $1,023 not $1,024. B. This statement is correct. Given the format '$9,999', the number 1023.99 will be formatted as $1,023 because the format rounds the number to no decimal places. C. This is incorrect because the format '$9,999' cannot display the number 10235.99; it exceeds the format's capacity. D. This is incorrect for the same reason as C, and the format would not change the thousands to hundreds. E. This statement is correct. If the number exceeds the maximum length of the format mask, which is 4 digits in this case, Oracle SQL displays a series of hash marks (#) instead of the number.
These formatting rules are described in the Oracle Database SQL Language Reference, which covers the TO_CHAR function and its number formatting capabilities.


NEW QUESTION # 136
......

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